Free Exam: Function
Number of Questions in Test: 24
Number of Questions in Preview: 5
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Given
f(x) = x[sup]2[/sup] + 1 , g(x) = [sqr]2x[/sqr]
The composition (f o g) (x) is
f(x) = x[sup]2[/sup] + 1 , g(x) = [sqr]2x[/sqr]
The composition (f o g) (x) is
| Type: | Multiple choice |
| Points: | 1 |
| Randomize answers: | Yes |
Question 2
Given f(x) = [sqr]-x + 1[/sqr] , g(x) = x[sup]2[/sup] - 8
The domain of the composition (f o g) (x) is
The domain of the composition (f o g) (x) is
| Type: | Multiple choice |
| Points: | 1 |
| Randomize answers: | Yes |
Question 3
Given
f(x) = 1 / (x + 1) and g(x) = 1 / (x - 1) ,
the composition (f o g) (0) is
f(x) = 1 / (x + 1) and g(x) = 1 / (x - 1) ,
the composition (f o g) (0) is
| Type: | Multiple choice |
| Points: | 4 |
| Randomize answers: | Yes |
Question 4
Find the inverse of the rational function f.
f(x) = (x + 1) / (x - 1)
f(x) = (x + 1) / (x - 1)
| Type: | Multiple choice |
| Points: | 4 |
| Randomize answers: | Yes |
Question 5
A possible graph for function f given by
f(x) = (x - 1)[sup]2[/sup] - 1
[img]http://i1196.photobucket.com/albums/aa401/tthung2/question_6.gif[/img] is
f(x) = (x - 1)[sup]2[/sup] - 1
[img]http://i1196.photobucket.com/albums/aa401/tthung2/question_6.gif[/img] is
| Type: | Multiple choice |
| Points: | 1 |
| Randomize answers: | Yes |